0,1x^2+36x-90=0

Solution for 0,1x^2+36x-90=0 equation:

0.1x^2+36x-90=0

a = 0.1; b = 36; c = -90;
Δ = b2-4ac
Δ = 362-4·0.1·(-90)
Δ = 1332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1332}=\sqrt{36*37}=\sqrt{36}*\sqrt{37}=6\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-6\sqrt{37}}{2*0.1}=\frac{-36-6\sqrt{37}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+6\sqrt{37}}{2*0.1}=\frac{-36+6\sqrt{37}}{0.2}
$